This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. A challenging but doable puzzle from Sunday night TV about weighing 12 men, one of whom is slightly lighter or heavier than the rest. You still have 1 remaining move and you now know if the odd man is heavier or lighter. There is also a see-saw on the island. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Otherwise the one who stayed is the oddly weighted one. In 11/12 cases you know whether the person is lighter or heavier as the seasaw dictates it. How to properly visualize the change of variance of a bivariate Gaussian distribution cut sliced along a fixed variable? 11 of them weigh the same and one of them is either slightly Weigh 1 against 2. You must figure out which. Software Engineer Author has 67 answers and 176.2K answer views 3 y Number each of the 12 people from 1 through 12. One of two things will happen: The seesaw will be perfectly balanced. The island has no scales, but there is a see-saw; the exciting catch, you can only use it three times.". Use the {{3 remaining with known weight solution}} from solution 1a. Weigh 9, 10, 11 vs 1, 2, 3. (Third Use), If the see saw is not balanced, remove one from each end. [10, 11, 12, 1] VS. [2, 3, 4, 5]. Each step here corresponds to one weighing. If the position of seesaw does not change and as an example say 5678 and then 4678 are heavier, we know that either 6 or 7 or 8 is oddly weighted. shift). You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. 2150 Condos - West Tower Phase 2 The exciting catch? Torsion-free virtually free-by-cyclic groups. The kid sitting on the end is the load. You have to figure out which Islander is the heaviest using a seesaw. You can weigh three combinations of men on the see-saw. sideline: S4 L1 L2 L3 L4 R4 Its similar to a puzzle about pool balls I put in my math brain teasers list a few years back but way harder. Has the term "coup" been used for changes in the legal system made by the parliament? 12 Islanders Teeter Totter Riddle There is an island with 12 islanders. Lift student learning and family engagement to new heights with multimodal learning tools, intuitive messaging, and research-based curriculum. Example for condition 1: put three "unknowns" against three "knowns". You signed in with another tab or window. Why do we kill some animals but not others? I wonder if this is the highest-viewed duplicate question of all time? run a simulation: go run . (First Use). (named after their starting position, L1 = Left 1, R1 = Right 1, S1 = Side 1 etc..), We now know that the odd islander are amongst S1 S2 S3 S4 It is impossible to know both for sure in only three steps." sideline: S1 S2 S3 S4, 2.A.1 if balanced Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Wow how did this even get 8 upvotesmind boggling. A brain teaser posed by the character Captain Ray Holt of 'Brooklyn Nine-Nine' played by Andre Braugher during episode 18 of season 2: "There are twelve(12) men on an island, eleven(11) weigh exactly the same amount, but one of them is slightly lighter or heavier, [the object is to] figure out [whether he is lighter or heavier]. So in principle, we should be able to solve the problem. How do you do it? (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. Connect and share knowledge within a single location that is structured and easy to search. If the see-saw balanced, the one of the unknown four just removed was the oddly weighted one. The exciting catch? ie. Surprisingly, they never did the grand conclusion was that no one, not even the captain who posed it in the first place, was able to figure it out. 2150 Condos - West Tower Phase 2. Answer explained - step by step Number the islanders 1 to 12 First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. New comments cannot be posted and votes cannot be cast. WRONG! Proceed to step 2. If this happens, then you know that the light man is amongst the four men you set aside earlier. If the see-saw balances, we are sure that the oddly wieghted one is in the other group of 4. Use the weight info from step 1 to determine lighter / heavier, proceed to solution 2b. Feel free to provide your own comment and I can delete this one. " Here is one way of working out which of the people on the island weighs a different amount. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (balanced) The odd man is in the group is in 9-12. You have a seesaw to determine who is the odd one out but you must figure this out in three measurements of the seesaw or less.. There was a problem preparing your codespace, please try again. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. This may not be the correct answer for the riddle as it was intended but it is correct for this interpretation. If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. Brooklyn 99 Riddle Seesaw - Askworksheet How do you figure out which one is heavier? There are 12 men on an island. Use Git or checkout with SVN using the web URL. Death by roo roo. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. Weigh 12 against 1 to find out whether 12 is heaver or lighter. If not balanced, the one going down is heavy. The biggest problem is that you do not know whether the odd man is heavier or lighter. seesaw: R1 L2 L3 L4 (heavy) L1 S2 S3 S4 Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. First weigh 1,2,3,4 against 5,6,7,8. Now put 7 on one end and 8 on the other. Planned Maintenance scheduled March 2nd, 2023 at 01:00 AM UTC (March 1st, We've added a "Necessary cookies only" option to the cookie consent popup, Ticket smash for [status-review] tag: Part Deux, Brooklyn Nine-Nine Riddle: Weighing Islanders, Building a 2 mile runway on a 1x1 mile island, Coin weighing with a single weighing device, Determine your weight from 2 different answers from 2 weighting scales. *** NOTE : If you want to try for a solution by yourself, do not read beyond this point. I like Rosa's answer squeeze until fatty confesses. A_ the equilibrium of the see-saw remains unchanged, therefore the man of a different weight is now amongst group 'def123' or SPOILER ALERT! Are you sure you want to create this branch? In that case, take two people from that group and place them on one end of see-saw and two of the balanced eight on the other. Say as example 1234 were lighter. Press question mark to learn the rest of the keyboard shortcuts. If the unknowns go down, you know that one of them is heavy. All our articles and reviews are written independently by the Netmums editorial team. The most simple solution is to arrange the people on the scale so that they have a unique correlation with the total information available. It only takes a minute to sign up. A tag already exists with the provided branch name. Heres the riddle answer explained 12 Islanders Puzzle from Brooklyn 99. Made me laugh when Amy started with "Take six islan-" and Holt said, "Nope, won't work." (seesaw measurement number 3). Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. I was lying there going through possibilities until 3 am when it hit me, and I got up and wrote down the solution. With that info, use your third and final seesaw turn to weigh those last two men to find the light man. The best answers are voted up and rise to the top, Not the answer you're looking for? I gave each of the 12 men a letter, A-L. Can You Solve the Brain Teaser of the 12 Men and a See-Saw? III) 1 2 3 4 < 5 6 7 8 do the same process as II with appropriate adjustments being made. Take four random men and set them aside. put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. New comments cannot be posted and votes cannot be cast. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. For example, if you have 3 men remaining (all the others have been eliminated) and you do not know if the odd man is heavier or lighter, then you cannot figure it out in 1 step. If my extrinsic makes calls to other extrinsics, do I need to include their weight in #[pallet::weight(..)]? Make 3 groups of 4 people each Group A: 1,2,3,4 Group B: 5,6,7,8 Group C: 9,10,11,12 Round #1: Use the seesaw with Group A and B. There is also a see-saw on the island. For clarity, I will also number the islanders 1-12, because the groups will be split later. If the seesaw reverses, ether 4 or 5 is the oddly weighted one. Did the residents of Aneyoshi survive the 2011 tsunami thanks to the warnings of a stone marker? (Second Use). The island has no escapes, but there is a seesaw. Hope you all sleep well after reading this. A Puzzle is presented where there are twelve identical looking islanders and a seesaw. Solution 1a. Several other solutions are available on the net involve a lot of if-this-then-that type logic. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (heavy) I later went back and refined it a little, so here it is. 1 v 12). One of two things will happen: 1) They are equal. I like this answer other than the fact that if "Condition 2.1.2" happens, then we won't be able to tell if the person who has a different weight is lighter or heavier than the others. If they are the same, 7 is different (and lighter). Brooklyn 99 And The 12 Men On An Island Puzzle - Utopia Mechanicus. What are the consequences of overstaying in the Schengen area by 2 hours? Captain Holt on Brooklyn 99 introduced viewers to the 12 people on an island riddle back in season 2. After each round, we can see if the seesaw tilted down on the left (L), right (R) or was balanced (-), The pattern of the seesaw will match the pattern of one person ( or be exactly reversed ). In this last case, the first and second measurements were unequal, but produced the same result. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. If they are equal, A4 is heavier. Would the reflected sun's radiation melt ice in LEO? You can only use it three times. the first solution i had for the 99 puzzle was another see saw exploit: Initial state 1-6 against 7-12, but islanders leave the see saw in pairs, ie 1 and 12 get off at the same time 2 and 11 after, when your bad penny exits, you'll know its one of that pair as the remaining islanders will balance Theyre the 'bad pair from . There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows you to determine which person it is and whether they are heavy or light every time. @Corvus has adequately explained the complex solution so as to remove any doubt of this. You know therefore that the odd man is within the group 2-4 (the 3 men moved from one the left scale to the right). Set it up so deduction eliminates everything else and your gold. The one who is heavier is the different man (and heavier). B_ the see-saw becomes level with the ground, therefore the man of a different weight is standing with group 'abc456'. Weigh A against B. If nothing happens, download Xcode and try again. Use 2 - Remove six(6) men from the see-saw, three(3) from both groups. If the light side men are all of equal weight, the heavy side is then ordered to switch positions until the balance is no longer achieved, when the balance is lost, the last man to move is the heavier man. It is impossible to know both for sure in only three steps.). 11 weigh exactly the same, but one of them is slightly lighter or heavier. The pattern for all islanders is below: person: A B C . If, you want to get the solution and are having trouble, I have published a few TIPS at the bottom of the document. If the see saw is not balanced, remove one from each end. The essence of the riddle is: "There are 12 men on an island. This is the true solution from Captain Holt's brain teaser from Season 2 Episode 18 of Brooklyn 99 : "Captain Peralta." Put any two groups on each side of the see-saw. If one is heavier they are the odd one otherwise it is 6. If A > B, then weigh A1, B1, and B2 against B3, B4, and C1. The first measurement of 4 vs. 4 was equal. It is easier than everyone makes it. (seesaw measurement number 3), (first make sure you have the heavy side on the left), seesaw: L1 L2 L3 L4 (heavy) R1 R2 R3 R4 :p, haha yeah loved the episode! The riddle, as you'll recall, is this: There are twelve men on an island. must figure this out in three measurements of the seesaw or less., (You need Go installed) The answer to 12 Men On An Island Riddle is " First weigh 1, 2, 3, 4 vs 5, 6, 7, and 8 on the seesaw to see if they are equal. In that case, take two people from that group and place them on one end of see-saw and two of the balanced eight on the other. I believe it was in. All of these men weigh exactly That's not true. The following steps become identical to those in Scenario 1., above. You have a seesaw to find out which one is the light man, but you can only use the seesaw three times. if balanced it is R4 - else it is the lighter of R3 and R2 The unique and extremely popular [citation needed] authority on pop culture since 2008. 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. If 9 and 10 are different, the different man is the lighter of the 9,10 comparison if 9,10,11 was lighter than 1,2,3, (and he is lighter); the different man is the heavier of the 9,10 comparison if 9,10,11 was heavier than 1,2,3 (and he is heavier). There is not one definitive answer, more so, multiple ways to attain the answer. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. If they are equal then. A tag already exists with the provided branch name. So, what is the 12 people on an island riddle and what is the answer? :D, Brooklyn 99 riddle: Weighing Islanders [duplicate]. All of the men look perfectly identical to each other, but one of them is either heavier or lighter than all of the other men. Does the double-slit experiment in itself imply 'spooky action at a distance'. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. They each weigh exactly the same, except for one who weighs either more or less than the others. Take 3 men from the group and measure against 3 neutral men from 1-8. The seesaw will NOT be perfectly balanced. sign in The second measurement was equal, so you know that the odd man is within the group 6-8. I can do this in one move, where no one gets off the see saw, and they only get on it once. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. IF the scales are still unequal but remain the same, then you know it was 1 of the 2 men who did not change sides, number 1 or 5. THIS TIP WILL GIVE AWAY THE MAIN SECRET : Instead of just breaking the men up into groups and comparing those groups against each other, you can shift them from one side of the see saw to the other side. The second measurement was unequal, but the balance of weight shifted. Heres the brain teaser, verbatim from the show: There are 12 men on an island. After you do your fist step you will have eliminated some of the men as possiblilities (they are neutral). we now know that the odd islander is S4. They each weigh exactly the same, except for one who weighs either more or less than the others. If they are equal, it is the remaining man not being measured. Try that and see where it takes you. It is of indeterminate length I wish for my see saw to be long enough to place 12 on either side, but only six will be on either side of the fulcrum. Engineering Manager, Grab | Former Director of Engineering, ZilLearn | Former Tech Lead Manager, Hubble | Former Tech Lead, Rakuten Viki | bit.ly/weiyuan. No Scenarios, No Cases, Just The Simple Answer.Instagram: https://www.instagram.com/lifeprojxFacebook: https://www.facebook.com/lifeprojx IF the 2 scales are equal, then you know the odd man is in the remaining group of 4. 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